Question

how to find the parallel line to y= negative 3X +5 and has a X intercept of three

Answer 1

Answer:

Therefore, equation of the line that passes through (3,0) and is parallel to the line

$y=-3x+5$

is

$y=-3x+9$

Step-by-step explanation:

Given:

$y=-3x+5$  ...Equation of line

The require line is Parallel to above line and has a X -intercept of three,

i.e y-coordinate will be zero and x-coordinate is 3 ,therefore the point

is  ( 3 , 0 )

To Find:

Equation of line passing through ( 3, 0) and is parallel to the line y=-3x+5

Solution:

$y=-3x+5$ ...........Given

Comparing with,  

$y=mx+c$

Where m =slope  

We get

$Slope = m = -3$

We know that parallel lines have Equal slopes.

Therefore the slope of the required line passing through (3 , 0) will also have the slope = m = -3.

Now the equation of line in slope point form given by

$(y-y_{1})=m(x-x_{1})$

Substituting the points and so we will get the required equation of the line,

$(y-0)=-3(x-3)=-3x+9\\\\y=-3x+9......Equation\ of\ line$

Therefore, equation of the line that passes through (3,0) and is parallel to the line

$y=-3x+5$

is

$y=-3x+9$