Question

(3y-4y+1)+(Negative Y to the power of 2+ Y -2

Answer 1

$(3y - 4 y +1)+(-y)^2+y-2$  $=(y+1)(y-1)$

Step-by-step explanation:

Given that

$(3y - 4 y +1)+(-y)^2+y-2$

$=(-y+1) + y^{2} +y-2$

$=-y +1+y^{2} +y -2$

$=y^{2} - 1$

$= y^2 -(1)^2$

$=(y+1)(y-1)$