Answer:
852 mL
Explanation:
Data of molarity means, moles of solute in 1L of solution
Let's convert the mass of solute, into moles
Mass / Molar mass = moles
125 g / 133.33 g/mol = 0.937 moles
In 1.1 moles of AlCl₃ are contained in 1L of solution
0.937 moles of AlCl₃ are contained in (0.937 mol . 1L) / 1.1 mol = 0.852L
Let's convert the L to mL
0.852L . 1000 mL/ 1L = 852 mL
Answer:
The volume of solution is 8.5*10^2 mL
Explanation:
Step 1: Data given
Molarity of an aluminium chloride solution = 1.1 M
Mass of aluminium chloride = 125.0 grams
Molar mass of aluminium chloride = 133.34 g/mol
Step 2: Calculate moles AlCl3
Moles AlCl3 = mass AlCl3 / molar mass AlCl3
Moles AlCl3 = 125.0 grams / 133.34 g/mol
Moles AlCl3 = 0.9375 moles
Step 3: Calculate volume of the solution
Molarity = moles / volume
Volume = moles / molarity
Volume = 0.9375 moles / 1.1 M
Volume = 0.852 L = 852 mL
Volume = 8.5 *10^2 mL
The volume of solution is 8.5*10^2 mL
