Answer:
[tex]x^{\frac{2}{7} } y^{-\frac{3}{5} } \\[/tex] i.e answer A.
Step-by-step explanation:
This question involves knowing the following power/exponent rule:
[tex]\sqrt[n]{x^m} = x^\frac{m}{n} \\\\so \sqrt[7]{x^2} = x^\frac{2}{7} \\\\and \\\\ \sqrt[5]{y^3} = y^\frac{3}{5} \\[/tex]
Next, when a power is on the bottom of a fraction, if we want to move it to the top, this makes the power become negative.
so the y-term, when moved to the top of the fraction, becomes:
[tex]y^{-\frac{3}{5} } \\[/tex]
So the answer is: [tex]x^{\frac{2}{7} } y^{-\frac{3}{5} } \\[/tex]
