Answer:
5.5879 m/s²
0.56961g
149.9976 mph
Explanation:
t = Time taken
u = Initial velocity = 0
v = Final velocity
s = Displacement = 0.25 miles
a = Acceleration
g = Acceleration due to gravity = 9.81 m/s²
[tex]s=ut+\frac{1}{2}at^2\\\Rightarrow 0.25\times 1609.34=0\times t+\frac{1}{2}\times a\times 12^2\\\Rightarrow a=\dfrac{0.25\times 1609.34\times 2}{12^2}\\\Rightarrow a=5.5879\ m/s^2[/tex]
The acceleration is 5.5879 m/s²
Dividing by g
[tex]\dfrac{a}{g}=\dfrac{5.5879}{9.81}\\\Rightarrow a=0.56961g[/tex]
The acceleration of these cars is 0.56961 times g
[tex]v=u+at\\\Rightarrow v=0+5.5879\times 12\\\Rightarrow v=67.0548\ m/s[/tex]
Converting mph
[tex]67.0548\times \dfrac{3600}{1609.34}=149.9976\ mph[/tex]
The speed is 149.9976 mph
A)The acceleration of the drag will be 5.5879 m/s².
B)The value you get compare with the acceleration of gravity will be 0.56961 g
C)The final speed of the drag racer will be 149.9976 mph.
The change of displacement with respect to time is defined as speed. Speed is a scalar quantity. It is a time-based component. Its unit is m/sec.
The displacement from the equation of motion is;
[tex]\rm s = ut + \frac{1}{2} at^2 \\\\ 0.25 \times 1609.34 = 0 \times t + \frac{1}{2} \times a \times 12^2 \\\\ a= \frac{0.25 \times 1609.34 \times 3 }{12^2} \\\\ a= 5.5879 \ m/sec^2[/tex]
If the acceleration is divided by the gravitational acceleration;
[tex]\rm \frac{a}{g} = \frac{5.5879}{9.81} \\\\ a= 0.56961 \ g[/tex]
From the Newton's first equation of motion;
[tex]\rm v= u+at \\\\ v=0+5,5879 \times 12 \\\\ v=67,0548 \ m/sec[/tex]
Conversion of the km/h into the miles per hour.
[tex]\rm =67.0548 \times \frac{3600}{1609.34} \\\\ =149.9976 \ mph[/tex]
Hence,the final speed of the tediousness racer will be 149.9976 mph.
To learn more about the velocity refer to the link;
https://brainly.com/question/862972
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