Answer:
The net charge on each lysine molecule would be -1.
Explanation:
R-COOH ↔ R-COO⁻
R-NH₃⁺
R'-NH₃⁺
Net charge = +1
R-COOH ↔ R-COO⁻
R-NH₂
R'-NH₃⁺
Net charge = 0
R-COOH ↔ R-COO⁻
R-NH₂
R'-NH₂
Net charge = -1
So at pH=13 (which is above 10.5) the net charge is -1.