Answer:
15144.268 m
Explanation:
Pressure: This can be defined as the ratio of force to the surface area in contact. T²he S. I unit of pressure is N/m²
P = F/A................... Equation 1
Where P = pressure, F = Force, A = Area of the submarine.
The pressure in water is
P = ρgh ............................ Equation 2
Where ρ = density of the water, g = acceleration due to gravity, h = depth.
Therefore,
ρgh = F/A
F = Aρgh.............................. Equation 3
Making h the subject of the equation,
h = F/(Aρg)............................ Equation 4
Given: F = 1.2×10⁶ N, A = πd²/4 where d = diameter = 10 cm = 0.1 m
A = 3.14(0.1)²/4 = 0.00785 m².
Constant: g = 9.8 m/s². ρ = 1030 kg/m³
Substitute into equation 4,
h = 1.2×10⁶/(1030×9.8×0.00785)
h = 15144.268 m.
Hence the submarine's maximum safe depth = 15144.268 m
