Solving the right triangle (round to the nearest tenth)

Answer:
idk
Step-by-step explanation:
idk sorry wish i could help u
Answer:
see explanation
Step-by-step explanation:
The sum of the 3 angles in a triangle = 180°
Subtract the sum of the given angles from 180 for B
B = 180° - (90 + 43)° = 180° - 133° = 47°
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tan43° = [tex]\frac{opposite}{adjacent}[/tex] = [tex]\frac{23}{b}[/tex]
Multiply both sides by b
b × tan43° = 23 ( divide both sides by tan43° )
b = [tex]\frac{23}{tan43}[/tex] ≈ 24.7 ( to the nearest tenth )
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sin43° = [tex]\frac{opposite}{hypotenuse}[/tex] = [tex]\frac{23}{c}[/tex]
Multiply both sides by c
c × sin43° = 23 ( divide both sides by sin43° )
c = [tex]\frac{23}{sin43}[/tex] ≈ 33.7 ( to the nearest tenth )