Answer:
a) p=0, b) p=0, c) p= ∞
Explanation:
In quantum mechanics the moment operator is given by
p = - i h’ d φ / dx
h’= h / 2π
We apply this equation to the given wave functions
a) φ = [tex]e^{ikx}[/tex]
.d φ dx = i k [tex]e^{ikx}[/tex]
We replace
p = h’ k [tex]e^{ikx}[/tex]
i i = -1
The exponential is a sine and cosine function, so its measured value is zero, so the average moment is zero
p = 0
b) φ = cos kx
p = h’ k sen kx
The average sine function is zero,
p = 0
c) φ = [tex]e^{-ax^{2} }[/tex]
d φ / dx = -a 2x [tex]e^{-ax^{2} }[/tex]
.p = i a g ’2x [tex]e^{-ax^{2} }[/tex]
The average moment is
p = (p₂ + p₁) / 2
p = i a h ’(-∞ + ∞)
p = ∞