Answer:
The four consecutive even integers are 4, 6, 8 and 10.
Step-by-step explanation:
Let the four consecutive even integers be [tex]x, x+2, x+4, x+6[/tex]
It is provided that the sum of these consecutive even integers is 28.
Solve for x as follows:
[tex]x+ x+2+ x+4+ x+6=28\\4x+12=28\\4x=16\\x=4[/tex]
The four consecutive even integers are:
[tex]x=4\\x+2=4+2=6\\x+4 = 4 +4 =8\\x+6=4+6=10[/tex]
Thus, the four consecutive even integers are 4, 6, 8 and 10.
