George had 1 sheet of paper. He cuts it into 6 inches by 5 inches, and 3 inches by 6 inches. What were the dimension dimensions and total area of his original sheet of paper? Explain.

Respuesta :

Answer:

The dimensions of the original sheet of paper are 8 inches by 6 inches.

The total area of the sheet of paper = 8 inches [tex]\times[/tex] 6 inches  = 48 [tex]inches^{2}[/tex]

Step-by-step explanation:

i) the two parts of the sheet of paper are 6 inches by 5 inches and 3 inches by   6 inches.

ii) therefore we see that the both parts have a 6 inch side.

iii) therefore we can say that the width of the sheet of paper is = 6 inches

iv) therefore we can also say that the length of the sheet of paper =  3  +  5 inches  = 8 inches.

v) therefore the dimensions of the original sheet of paper are 8 inches by 6 inches.

vi) therefore the total area of the sheet of paper = 8 inches [tex]\times[/tex] 6 inches

                                                                          = 48 [tex]inches^{2}[/tex]

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