Question

Ammonium fluoride is considered which of the following?
a. molecular compound
b. molecular element
c. ionic compound
d. atomic element
e. none of the above

Answer 1

Answer:

c. ionic compound

Explanation:

Ammonium fluoride -

It is an inorganic salt , which has the molecular formula of $NH_4F$ .

As it is a salt , it is ionic in nature , i.e. , it has a cationic part and an anionic part , i.e. ,

$NH_4^{+}$ is the cationic species .

And

$F^-$ is the anionic species.

$NH_4F$ is a crystalline solid , just like most of the salts , and has a very s alt salty taste to it.

Hence, from the given option ,

The correct option is ionic compound.

Ammonium fluoride is the inorganic compound with the formula NH4F. It crystallizes as small colourless prisms, having a sharp saline taste, and is exceedingly soluble in water.

Answer 2

By definition, the correct answer is option C. ammonium fluoride is considered ionic compound

Ammonium fluoride is an inorganic compound with the formula NH₄F.

An ionic compound is made up of positive and negative ions, held together by electrostatic forces of attraction.

Electrostatic attraction is not limited to a single ion, but each of them surrounds itself with the maximum possible number of ions of opposite charge, forming a three-dimensional ionic crystal lattice.

Ionic compounds do not form independent molecules.

In an ionic compound, a metallic atom becomes a positive ion (called a cation), while a non-metallic atom becomes a negative ion (called an anion).

In this case:

• NH₄⁺ IS the cationic species .
• F⁻ is the anionic species.

Finally, NH₄F is a ionic compound.

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