Question

The second of two numbers is 4 times the first. Their sum is 45.

Answer 1

Question:

The second of two numbers is 4 times the first. Their sum is 45. Find the numbers

Answer:

The two numbers are 9 and 36

Solution:

Let the two numbers be "x" and "y"

Let "x" be the first number and "y" be the second number

Given that the sum of numbers is 45

x + y = 45 ------- eqn 1

Also, given that, second of two numbers is 4 times the first

second number = 4 times the first

y = 4x ------- eqn 2

Substitute eqn 2 in eqn 1

x + 4x = 45

5x = 45

x = 9

Substitute x = 9 in eqn 2

y = 4(9)

y = 36

Thus the two numbers are 9 and 36