Respuesta :
Answer:
- [010]_{R} = { s ∈ A | the first three bits of s are 010}
- [1011]_{R} = { s ∈ A | the first three bits of s are 101}
- [11111]_{R} = { s ∈ A | the first three bits of s are 111}
- [01010101]_{R} = { s ∈ A | the first three bits of s are 010}
Explanation:
We say ∼ is an equivalence relation on a set A if it satisfies the following three properties:
a) reflexive: for all a∈A, a∼a.
b) symmetry: for all a,b∈A, if a∼b then b∼a.
c) transitivity: for all a,b,c∈A, if a∼b and b∼c then a∼c.
Given
A = Set of all bit strings that have a length of at least 3
R ={(x,y) first three bit of x and y are same
a) the equivalence classes of 010 will contain all bit strings that have as the first three digits 010
[010]_{R} = { s ∈ A | the first three bits of s are 010}
b) the equivalence classes of 1011 will contain all bit strings that have as the first three digits 101
[1011]_{R} = { s ∈ A | the first three bits of s are 101}
c) the equivalence classes of 11111 will contain all bit strings that have as the first three digits 111
[11111]_{R} = { s ∈ A | the first three bits of s are 111}
d) the equivalence classes of 01010101 will contain all bit strings that have as the first three digits 010
[01010101]_{R} = { s ∈ A | the first three bits of s are 010}