Solving a right triangle (round to the nearest tenth) ‼️‼️‼️

Answer:
see explanation
Step-by-step explanation:
The sum of the 3 angles in a triangle = 180°
Subtract the sum of the given angles from 180 for B
B = 180° - (90 + 47)° = 180° - 137° = 43°
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tan47° = [tex]\frac{opposite}{adjacent}[/tex] = [tex]\frac{a}{14}[/tex]
Multiply both sides by 14
14 × tan47° = a, thus
a ≈ 15.0 (to the nearest tenth )
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cos47° = [tex]\frac{adjacent}{hypotenuse}[/tex] = [tex]\frac{14}{c}[/tex]
Multiply both sides by c
c × cos47° = 14 ( divide both sides by cos47° )
c = [tex]\frac{14}{cos47}[/tex] ≈ 20.5 ( to the nearest tenth )