Question

In the deep space between galaxies, the density of atoms is as low as 106 atoms/m3, and the temperature is a frigid 2.7 K. What is the pressure (in Pa)?

Answer 1

Answer: 3.73 × 10^-17 Pa

Explanation:

N/V= 10^6 atom/m^3

T=2.7k

Kb=1.38 ×10^-23 J/K

NA= 6.02 × 10^23 mol^-1

R= 8.31J/mol.K

PV= NaKbT

PV= N/V × KbT

P= 10^6 × 1.38 × 10^-23× 2.7

Pressure= 3.73×10^-17 Pa

Answer 2

The pressure in pascal of the deep space whose density of atoms is as low as 10⁶ atoms/m3 is 3.73 × 10-¹⁷ Pa.

How to calculate pressure?

The pressure of a space can be calculated using the following expression:

PV= N/V × KbT

Where;

• P = pressure
• V = volume
• Kb = temperature constant
• T = temperature
• R = gas law constant

• N/V = 10⁶ atom/m³
• T = 2.7K
• Kb = 1.38 ×10^-23 J/K
• NA= 6.02 × 10²³ mol-¹
• R= 8.31J/mol.K

P = N/V × KbT

P= 10⁶ × 1.38 × 10-²³ × 2.7

Pressure = 3.73 × 10-¹⁷ Pa

Therefore, the pressure in pascal of the deep space whose density of atoms is as low as 10⁶ atoms/m3 is 3.73 × 10-¹⁷ Pa.

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