Question

3. For the reaction: 2X + 3Y 3Z, the combination of 2.00 moles of X with 2.00
moles of Y produces 1.75 moles of Z. What is the percent yield of this reaction?

Answer 1

Answer:

Explanation:

For the reaction: 2X + 3Y = 3Z, the combination of 2.00 moles of X with 2.00

moles of Y produces 1.75 moles of Z

      2 mol       2 mol   1.75 mol

       2X     +    3Y       =    3Z

need 2 mol  3 mol     to give 3 mol

3 mol Z/3 mol Y=  1 to 1

should get 2 mol Z

1.75/2 =87.5 % yield

Answer 2

87.5 % per cent yield of this reaction when the combination of 2.00 moles of X with 2.0 moles of Y produces 1.75 moles of Z

What are moles?

A mole is defined as 6.02214076 × $10^{23}$of some chemical unit, be it atoms, molecules, ions, or others. The mole is a convenient unit to use because of the great number of atoms, molecules, or others in any substance.

For the reaction: 2X + 3Y = 3Z, the combination of 2.00 moles of X with 2.00 moles of Y produce 1.75 moles of Z.

2 mol    +    2 mol   =  1.75 mol

2X     +    3Y       =    3Z

Need 2 mol  3 mol  to give 3 mol

3 mol Z ÷3 mol Y=  1 ÷ 1

should get 2 mol Z

The per cent yield of this reaction:

1.75 ÷ 2 = 87.5 % yield

Hence, 87.5 % per cent yield of this reaction.

Learn more about moles here:

https://brainly.com/question/8455949

#SPJ2