To solve this problem we will apply the concepts related to the magnitude of the electric field. Defined as the proportion of the electric potential per unit of distance, that is,
[tex]E = \frac{V}{d}[/tex]
Where E is the magnitude of the electric field between the plates, V is the potential difference between the plates, and d is the separation of the plates
The breakdown field of air is [tex]3.0*10^6[/tex] N/C.
Replacing we have that the Potential is
[tex]V = Ed[/tex]
[tex]V = (3.0*10^6)(1.89*10^{-3})[/tex]
[tex]V = 5670V[/tex]
Therefore the potential difference between you and your friend just before the spark is 5670V