Question

The following reaction takes place at high temperatures.
Solid chromium(III) oxide reacts with liquid aluminum to give liquid chromium and liquid aluminum oxide.
Write a balanced chemical equation (include the states of matter).

Answer 1

Answer:

$Cr_2O_3 (s) + 2Al (l)$ ⇒ $2Cr (l) + Al_2O_3 (l)$

Answer 2

The balanced chemical equation (including the states of matter) is

Cr₂O₃(s) + 2Al(l) ⇒ 2Cr(l) + Al₂O₃(l)

Solid chromium(III) oxide reacts with liquid aluminum to give liquid

chromium and liquid aluminum oxide. This reaction occurs at high

temperature because the reactivity is increased under this condition.

TYhe liquid aluminium is oxidized to form liquid aluminum oxide and the

Solid chromium(III) oxide is reduced to form liquid chromium and can be

referred to as  a redox reaction.

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