Question

The absolute temperature of a gas is increased four times while maintaining a constant volume. What happens
pressure of the gas?
It decreases by a factor of four.
It increases by a factor of four.
it decreases by a factor of eight.
o tincreases by a factor of eight.

Answer 1

Answer:

It increases by a factor of four

Explanation:

Boyle's Law : At constant temperature , the volume of fixed mass of a gas is inversely proportional to its pressure.

pV = K.......(1)

pV = constant

Charles law : The volume of the gas is directly proportional to temperature at constant pressure.

V = KT

or V/T = K = constant ....(2)

Applying equation (1) and (2)

$\frac{PV}{T}=K$

$\frac{P_{1}V_{1}}{T_{1}}=\frac{P_{2}V_{2}}{T_{2}}$

According to question ,

T2 = 4 (T1)

V2 = V1

Put the value of T2 and V2 , The P2 can be calculated,

$\frac{P_{1}V_{1}}{T_{1}}=\frac{P_{2}V_{1}}{4T_{1}}$

V1 and V1 cancel each other

T1 and T1 cancel each other

We get,

$P1=\frac{P2}{4}$

or

P2 = 4 P1

So pressure increased by the factor of four

Answer 2

Answer:

b

Explanation:

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