Question

How strong is the electric field between two parallel plates 4.8 mm apart if the potential difference between them is 220 V?

Answer 1

Answer:

Electric field, E = 45833.33 N/C

Explanation:

Given that,

Separation between the plates, d = 4.8 mm = 0.0048 m

The potential difference between the plates, V = 220 volts

We need to find the electric field between two parallel plates. The relation between the electric field and electric potential is given by :

$V=E\times d$

$E=\dfrac{V}{d}$

$E=\dfrac{220}{0.0048}$

E = 45833.33 N/C

So, the electric field between two parallel plates is 45833.33 N/C. Hence, this is the required solution.

Answer 2

The electric field between the plates is 45833.33 N/C.

Electric Field

Given that the separation d between the plates is 4.8 mm and the potential difference V between the plates is 220 V.

The electric field E between the plates can be calculated by the formula given below.

$E =\dfrac {V}{d}$

Substituting the values in the above equation, we get

$E = \dfrac {220}{0.0048}$

$E = 45833.33 \;\rm N/C$

Hence we can conclude that the electric field between the plates is 45833.33 N/C.

To know more about the electric field, follow the link given below.

https://brainly.com/question/12757739.