Respuesta :

[tex]g(x) = 2(x-2)^2-5 \text{ is equivalent to } 2x^2-8x+3[/tex]

Solution:

Given expression is:

[tex]f(x) = 2x^2-8x+3[/tex]

We have to find the equivalent expression

[tex]\mathrm{Write}\:2x^2-8x+3\:\mathrm{in\:the\:form:\:\:}x^2+2ax+a^2[/tex]

[tex]f(x) = 2x^2-8x+3[/tex]

[tex]\mathrm{Factor\:out\:}2[/tex]

[tex]2\left(x^2-4x+\frac{3}{2}\right)[/tex]

[tex]\mathrm{Add\:and\:subtract}\:\left(-2\right)^2\:[/tex]

[tex]2\left(x^2-4x+\frac{3}{2}+\left(-2\right)^2-\left(-2\right)^2\right)[/tex]

Simplify the above equation

[tex]2(x^2-4x + \frac{3}{2} + 4 -4)\\\\2(x^2-4x +4 + \frac{3}{2} - 4)\\\\2(x^2-4x +4 -\frac{5}{2}) ------- eqn 1[/tex]

Using the algebraic identity,

[tex]x^2+2ax+a^2=\left(x+a\right)^2[/tex]

Therefore,

[tex]x^2-4x+4=\left(x-2\right)^2[/tex]

Substitute the above in eqn 1

[tex]2((x-2)^2-\frac{5}{2})[/tex]

Simplify the above equation by multiplying 2 with terms inside the bracket

[tex]2(x-2)^2 -5[/tex]

Thus the equivalent expression is [tex]g(x) = 2(x-2)^2-5[/tex]

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