A team of dogs drags a 70.9 kg sled 1.24 kmover a horizontal surface at a constant speed.The coefficient of friction between the sledand the snow is 0.193.The acceleration of gravity is 9.8 m/s2.Find the work done by the dogs.Answer in units of kJ.

Respuesta :

Answer:

166.284 KJ

Step-by-step explanation:

We are given that

Mass of sled =70.9 kg

Displacement of sled=1.24 km

Coefficient of friction=[tex]\mu=[/tex]0.193

Acceleration due to gravity=[tex]g=9.8m/s^2[/tex]

We have to find the work done by the dogs in units KJ

Friction force=[tex]\mu mg[/tex]

Friction force =f=[tex]0.193\times 70.9\times 9.8=134.1N[/tex]

Force applied by team of dogs=Friction force

F=f=134.1 N

Work done=[tex]F\times s[/tex]

We have s=1.24 km=[tex]1.24\times 1000=1240m[/tex]

1 km= 1000 m

Work done=[tex]134.1\times 1240=166284 J[/tex]

1 KJ=1000J

Work done=[tex]\frac{166284}{1000}=166.284KJ[/tex]

Hence, the work done by the dogs=166.284 KJ

ACCESS MORE
EDU ACCESS
Universidad de Mexico