Question

A triangle has vertices at A(-7, 6), B(4,9), C(-2, -3). What are the coordinates of each vertex if the triangle is translated 4 units right and 6 units down?

Answer 1

Answer:

$A'(-3,0),B'(8,3),C'(2,-9)$

Step-by-step explanation:

we know that

the triangle is translated 4 units right and 6 units down

so

The rule for the translation is

$(x,y) -----> (x+4,y-6)$

Applying the rule for the translation find the image of each vertex

1) $A(-7,6) -----> A'(-7+4,6-6)$

$A(-7,6) -----> A'(-3,0)$

2) $B(4,9) -----> B'(4+4,9-6)$

$B(4,9) -----> B'(8,3)$

3) $C(-2,-3) -----> C'(-2+4,-3-6)$

$C(-2,-3) -----> C'(2,-9)$