Question

An 8900-pF capacitor holds plus and minus charges of 1.85×10−7 C . Part A What is the voltage across the capacitor?

Answer 1

Voltage is the ratio of stored charge to the capacitance of the capacitor.

The voltage across the capacitor is 20.79 V.

What is voltage?

Voltage is the electromagnetic force, which forces the charged electron between the two points of a conductor.

It can be given as,

$V=\dfrac{q}{C}$

Here is the $q$ is the stored charge and $C$ is the capacitance of the capacitor.

Given information-

The capacitance of the capacitor is 8900 pF.

The charge of the capacitor is $1.85\times10^{-7}$.

Thus to find the voltage across the capacitor, put the values in the above formula as,

$V=\dfrac{q}{C}\\V=\dfrac{1.85\times10^{-7}}{8900}\\V=20.79 \rm V$

Hence the voltage across the capacitor is 20.79 V.

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