The volume, V, of gas varies inversely with the pressure, P, on it. If the volume is 320 cm^3 under pressure of 40 kg/cm^2, what pressure has to be applied to have a volume of 200 cm^3?



Fill in the blank:

Answer: _________ kg/cm^2

Respuesta :

The pressure [tex]64kg/cm^{2}[/tex] has to be applied to have a volume of [tex]200cm^{3}[/tex]

Explanation:

According to Boyle's law, for a fixed amount of gas, the volume and pressure are inversely proportional.

[tex]P_{1} \cdot V_{1}=P_{2} \cdot V_{2}[/tex]

Substituting the values, we get,

[tex]40 \times 320=P_{2} \times 200[/tex]

Dividing both sides by 200,

[tex]\frac{40 \times 320}{200}=P_{2}[/tex]

Simplifying the terms, we get,

[tex]\begin{aligned}\frac{12800}{200} &=P_{2} \\64 &=P_{2}\end{aligned}[/tex]

Thus, the pressure [tex]64kg/cm^{2}[/tex] has to be applied to have a volume of [tex]200cm^{3}[/tex]

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