Answer:
13
Step-by-step explanation:
The given expression is (3-2i)(3-2i)
This is of the form (a-b)(a+b)
This is equivalent to [tex]\[a^{2}-b^{2}\][/tex], where a = 3 and b=2i
= [tex]\[3^{2}-(2i)^{2}\][/tex]
= [tex]\[9-4i^{2}\][/tex]
But [tex]\[i^{2} = -1\][/tex]
= [tex]\[9-4*(-1)\][/tex]
= [tex]\[9+4\][/tex]
= [tex]\[13\][/tex]
Hence the value of the expression (3-2i)(3-2i) is 13.
