Question

A satellite is placed in orbit 8.52 x 105 m above the surface of Jupiter. Jupiter has a mass of 1.90 x 1027 kg and a radius of 7.14 x 107 m. Find the orbital speed of the satellite.

Answer 1

Answer: The orbital speed of the satellite is 4.214×10^4m/s

Explanation: Given:

Mass of Jupiter= 1.9×10^27Kg

Radius of Jupiter= 7.14×10^7m

Orbital speed of satellite is given by the equation:V = SQRT(G× M/ R)

But G= 6.673×10^-11Nm^2/Kg^2

V= SQRT (6.673×10^-11)×1.9×10^27)/7.14×10^7

V= SQRT1.776×10^9

V= 42,142.6515m/s=4.214×10^4m/s