Evaluate
c
2

3
+
6
d
2
c

−3+
d
6

start fraction, c, divided by, 2, end fraction, minus, 3, plus, start fraction, 6, divided by, d, end fraction when
c
=
14
c=14c, equals, 14 and
d
=
3


Respuesta :

Answer:

The answer = 6

Step-by-step explanation:

Given expression:

[tex]\frac{c}{2}-3+\frac{6}{d}[/tex]

To evaluate the  given expression, when [tex]c=14[/tex] and [tex]d=3[/tex]

Solution:

We have:

[tex]\frac{c}{2}-3+\frac{6}{d}[/tex]

Plugging in [tex]c=14[/tex] and [tex]d=3[/tex] in the given expression, to evaluate.

⇒ [tex]\frac{14}{2}-3+\frac{6}{3}[/tex]

Evaluating:

⇒ [tex]7-3+2[/tex]

6 (Answer)

Answer:

hmm 6

Step-by-step explanation:

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