Answer:
27x + 8 = (3[tex]\sqrt[3]{x}[/tex] + 2)([tex]9\sqrt[3]{x^{2} } - 6\sqrt[3]{x} + 4[/tex]) is the final factorized form of the given polynomial.
Step-by-step explanation:
i) 27x + 8 = [tex]3^{3}(\sqrt[3]{x} } )^3 + 2^{3}[/tex]
ii) From the formula [tex]a^{3} + b^{3} = (a + b)(a^{2} - ab + b^{2} )[/tex] we can write for the given polynomial
iii) therefore 27x + 8 = ([tex]3\sqrt[3]{x}[/tex] + 2)([tex]9\sqrt[3]{x^{2} } - 6\sqrt[3]{x} + 4[/tex]) is the final factorized form of the given polynomial.