Question

A particle is moving in a plane with constant radial velocity $\dot{r}$ = 2.11 m/s, having started at the origin. It also has a constant angular velocity $\dot{\theta}$ = 2.55 rad/s. When the particle is 2.64 m from the origin, what is the magnitude of its velocity in m/s?

Answer 1

Answer:Magnitude of velocity =14.20m/s

Explanation:

The equation for the magnitude of velocity is given by:

/V/= SQRT r^2 +r^2×angular velocity ^2

/V/ = SQRT 2.11^2+ 2.64^2+2.55^2

/V/= SQRT 4.4521 + (6.9696 ×6.5025)

/V/=SQRT 201.768

/V/=14.20m/s