Answer:
Step-by-step explanation:
Alright, lets get started.
The given equation is :
[tex]1+2e^{x+1}=9[/tex]
Subtracting 1 in both sides
[tex]1+2e^{x+1}-1=9-1[/tex]
[tex]2e^{x+1}=8[/tex]
Dividing 2 in both sides
[tex]e^{x+1}=\frac{8}{2}[/tex]
[tex]e^{x+1}=4[/tex]
Taking log on both sides
[tex]loge^{(x+1)}=log4[/tex]
[tex](x+1)loge=log4[/tex]
Plugging the value of log e as 1
[tex]x+1=log4[/tex]
[tex]x=log4-1[/tex] ..................... Answer
Hope it will help :)
