Question

The electric force between two identical positively charged ions is 33 × 10 − 9 N when they are 0.50 nm apart. How many electrons are missing from each ion?

Answer 1

Answer:

There are 5.98 electrons are missing from each ions.

Explanation:

Given that,

The electric force between two identical charges is, $F=33\times 10^{-9}\ N$  

The distance between the charges, $d=0.5\ nm=0.5\times 10^{-9}\ m$

The electric force between charges is given by :

$F=\dfrac{kq^2}{d^2}$

$q=\sqrt{\dfrac{Fd^2}{k}}$

$q=\sqrt{\dfrac{33\times 10^{-9}\times (0.5\times 10^{-9})^2}{9\times 10^9}}$

$q=9.57\times 10^{-19}\ C$

Let there are n number of electrons are missing from each ions. It is given by :

$n=\dfrac{q}{e}$

$n=\dfrac{9.57\times 10^{-19}}{1.6\times 10^{-19}}$

n = 5.98 electrons

So, there are 5.98 electrons are missing from each ions. Hence, this is the required solution.