Question

ilver bromide is used to coat ordinary black-and-white photographic film, while high-speed film uses silver iodide. (a) When 56.6 mL of 5.00 g/L AgNO3 is added to a coffee-cup calorimeter containing 56.6 mL of 5.00 g/L NaI, with both solutions at 25°C, what mass of AgI forms?

Answer 1

Answer:

Mass of AgI formed=0.352g

Explanation:

AgNO3 + NaI ----‐>AgI + NaNO3

Volume of AgNO3 =5g/L

Mass of AgNO3 =C×V=0.25g

n(AgNO3)= m/Mr=0.0015mol

For NaI

V= 5g/l

Mass= C×v=0.25g

n=m/Mr=0.0017mol

n=0.0015mol

Mass=n× mr=0.352g

Answer 2

From the stoichiometry of the reaction, 0.45 g of AgI is formed.

First of all we have to obtain the molar concentration of AgNO3 using the formula;

Mass concentration = molar concentration × molar mass

Molar concentration = Mass concentration /molar mass

Molar concentration = 5.00 g/L/170 g/mol = 0.029 M

Number of moles of AgNO3  = molar concentration × volume

=  0.029 M  × 56.6/1000 L= 0.0016 moles

Molar concentration of NaI =  5.00 g/L /150 g/mol = 0.033 M

Number of moles of NaI = 0.033 M  × 56.6/1000 L = 0.0019 moles

The reaction equation is;

AgNO3 + NaI -----> AgI + NaNO3

Since the reaction is 1:1 then AgNO3 is the limiting reactant.

Mass of AgI formed = 0.0016 moles  × 235 g/mol = 0.45 g

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