Question

A bullet is fired straight up from a gun with amuzzle velocity of 208 m/s.Neglecting air resistance, what will be itsdisplacement after 8.9 s?

Answer 1

Displacement after 8.9 seconds  is 1462.68 m

Explanation:

We have equation of motion s = ut + 0.5 at²

        Initial velocity, u = 208 m/s

        Acceleration, a = -9.81 m/s²  

        Time, t = 8.9 s      

     Substituting

                      s = ut + 0.5 at²

                      s = 208 x 8.9 + 0.5 x -9.81 x 8.9²

                      s = 1462.68 m

      Displacement after 8.9 seconds  is 1462.68 m