Answer:
Therefore the difference in volume of the two lamps = 96 [tex]cm^{3}[/tex] - 32 [tex]cm^{3}[/tex] = 64 [tex]cm^{3}[/tex]
Step-by-step explanation:
i) volume of first lava lamp = base [tex]\times[/tex] height = 96 [tex]cm^{3}[/tex]
ii) base of first lamp = base of second lamp = base
iii) height of first lamp = height of second lamp = height
iv) volume of second lamp = [tex]\frac{1}{3}[/tex] [tex]\times[/tex] base [tex]\times[/tex] height
therefore volume of second lamp = [tex]\frac{1}{3}[/tex] [tex]\times[/tex] 96 [tex]cm^{3}[/tex] = 32 [tex]cm^{3}[/tex]
v) therefore the difference in volume of the two lamps = 96 [tex]cm^{3}[/tex] - 32 [tex]cm^{3}[/tex] = 64 [tex]cm^{3}[/tex]