A gas occupies 547 L at 331K. Find its volume at 376K. You must show all of your work to receive credit. Also, name the gas law you used to solve the problem.

1 point- Identify which of the Gas Laws you used to solve the problem.

3 points- Show your work on solving the problem.


A gas occupies 97 mL at 130 kPa. Find its volume at 225 kPa You must show all of your work to receive credit. Also, name the gas law you used to solve the problem.


1 point- Identify which of the Gas Laws you used to solve the problem.

3 points- Show your work on solving the problem.


PLEASE HELP IM SO LOST ILL MARK BRAINLIEST

Respuesta :

Answer:

Explanation:

The gas law used to solve the problems is Charles's law . It states with no pressure or energy change, the volume of an ideal gas is directly proportional to its temperature in Kelvin.

A gas occupies 547 L at 331K.

So its volume at 376K is

= 547 / 331 * 376

= 621.37 L

The gas law used to solve the problem is Boyle's law . It states with no temperature or energy change, the volume of an ideal gas is inversely proportional to its pressure.

A gas occupies 97 mL at 130 kPa.

So its volume at 225 kPa is

= 97 * 130 / 225

= 56.04 mL

#1

Apply charles law

[tex]\\ \rm\Rrightarrow V1T2=V2T1[/tex]

[tex]\\ \rm\Rrightarrow V2=\dfrac{V1T2}{T1}[/tex]

[tex]\\ \rm\Rrightarrow V2=\dfrac{547(376)}{341}[/tex]

[tex]\\ \rm\Rrightarrow V2=603.1L[/tex]

#2

Apply boyles law

[tex]\\ \rm\Rrightarrow P1V1=P2V2[/tex]

[tex]\\ \rm\Rrightarrow 130(97)=225V2[/tex]

[tex]\\ \rm\Rrightarrow V2=56.04mL[/tex]

ACCESS MORE