Question

A nitrogen laser pulse with a wavelength of 337 nm contains 3.83 mJ of energy. How many photons does it contain?

Answer 1

Answer:

number of photon will be equal to $5.827\times 10^{15}photon$

Explanation:

We have given wavelength of nitrogen laser pulse is 337 nm

So wavelength $\lambda =337nm=337\times 10^{-9}m$

Velocity of light $c=3\times 10^8m/sec$

Plank's constant $h=6.6\times 10^{-34}Js$

So energy of each photon $E=\frac{hc}{\lambda }=\frac{6.6\times 10^{-34}\times 3\times 10^8}{337\times 10^{-9}}=5.8\times 10^{-19}J$

Total energy is given = 3.38 mJ = 0.00338 J

So number of photon will be equal to $=\frac{0.00338}{5.8\times 10^{-19}}=5.827\times 10^{15}photon$

So number of photon will be equal to $5.827\times 10^{15}photon$