Question

What mass (in g) of solute is contained in 764.9 mL of a 0.137 M solution of glucose, C6H12O6? Enter your answer with 3 significant figures and no units.

Answer 1

Answer:

18.9

Explanation:

Given data

• Volume (V): 764.9 mL = 0.7649 L

• Molar concentration (C): 0.137 M = 0.137 mol/L

We can find the moles (n) of glucose using the following expression.

n = C × V

n = 0.137 mol/L × 0.7649 L

n = 0.105 mol

The molar mass of glucose is 180.16 g/mol. The mass corresponding to 0.105 moles is:

m = 0.105 mol × 180.16 g/mol = 18.9 g