Question

$g(x) = (x + {x}^{2} ) {}^{3} . =$
Find the value of g(-1)​

Answer 1

Answer:

$g(-1) =[(-1)+(-1)^{2}]^{3} = [-1 + (-1)^{2}]^{3} = [-1 + 1]^{3} = 0^{3} = 0$

:)