Question

An antelope is running away at 15 mph after being startled by a predator. The antelope then slows to rest. What is its change in velocity?

Answer 1

The change in velocity is -15 mph (-6.7 m/s)

Explanation:

The change in velocity of an object is given by

$\Delta v = v-u$

where

v is the final velocity of the object

u is its initial velocity

For the antelope in this problem, we have:

u = 15 mph is the initial velocity

v = 0 is the final velocity (the antelope slows to rest)

Therefore, its change in velocity is

$\Delta v = 0-15 = -15 mph$

We can also convert into m/s, keeping in mind that:

$1mi = 1609 m\\1 h = 3600 s$

And we find,

$\Delta v = -15 \frac{mi}{h} \cdot \frac{1609 m/mi}{3600 s/h}=-6.7 m/s$

Learn more about velocity:

brainly.com/question/5248528

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