Question

You are given a semiconductor resistor made from silicon with an impurity concentration of resistivity 1.00×10−3Ωm1.00×10−3Ωm. The resistor has a height of HH =0.5 mmmm, a length of LL = 2 mmmm, and a width of WW = 1.25 mmmm. The resistor can absorb (dissipate) up to PP = 7.81WW. What is the resistance of the resistor (RR), the maximum voltage (VV), and the maximum current (II)?

Answer 1

Answer:

The resistance (R) of the resistor is 2.4 ohm

The maximum voltage (V) is 4.33V

The maximum current (I) is 1.80A

Explanation:

Resistance (R) = resistivity×length/area

Resistivity = 0.003 ohm meter, length = 2mm = 2/1000 = 0.002m, width = 1.25mm = 1.25/1000 = 0.00125m, height = 0.5mm = 0.0005m, area = width × height = 0.00125m × 0.0005m = 6.25×10^-7m^2

R = 0.003×0.002/6.25×10^-7 = 3.2 ohm

Power (P) = V^2/R

V^2 = P × R = 7.81 × 3.2= 24.992

V = √24.992 = 4.99V

P = IV

I = P/V = 7.81/4.99 = 1.57A