Question

What is the x-component of the force on the charge located at x = 8 cm given that q = 1.1 μC in N?

Answer 1

Answer:

Answer is = 12.3 x 10^6 N

Explanation:

We need to calculate force on the charge which is in Newtons:

Formula is = K q1q2/r^2

k is constant depeneds on the permitivity of the medium and its value is 9x10^9 Nm^2/C^2

q1 and q2 are charges and r is the distance between these two charges so just by putting values we get F= 9x10^9 x 1.1x10^-6/(8x10^-2)^2 (we get the above answer in newton)

Answer 2

The x component of the force on the charged particle is $1.54\times 10^6\;\rm N$

How do you calculate the force?

Given that the particle has a charge of q = 1.1 μC and is located at a distance of x = 8 cm. The force on a charged particle can be given as below.

$F = \dfrac {kq_1q_2}{r^2}$

Where k is the permittivity constant that is 9x10^9 Nm^2/C^2 and r is the distance.

Substituting the values in the above equation.

$F=\dfrac {9\times 10^9\times 1.1\times 10^{-6}}{(8\times 10^{-2})^2}$

Force $F = 1.54\times 10^6\;\rm N$

Hence we can conclude that the x component of the force on the charged particle is $1.54\times 10^6\;\rm N$

To know more about the force, follow the link given below.

https://brainly.com/question/26115859.