Answer:
q₁ = q₂ = Q = 14.8 pC
Explanation:
Given that
q₁ = q₂ = Q = ?
Distance between charges = r =7.3 cm = 0.073 m
Combined electric field = E₁ + E₂ = E = 50 N/C
Using formula
[tex]E=2\frac{kQ}{r^2}[/tex]
Rearranging for Q
[tex]Q= \frac{Er^2}{2k}\\\\Q=\frac{(50)(.005329)}{2\times 9\times 10^9}[/tex]
[tex]Q=14.8\times 10^{-12}\, C\\\\Q=14.8\, pC[/tex]