In the mouse, gene B can produce black pigment from a colorless precursor molecule. A mouse having at least one B allele can produce black pigment, whereas the homozygous recessive mouse (bb) cannot and is albino. The agouti locus (A) can convert the black pigment to brown in the presence of at least one dominant A allele, whereas the homozygous recessive (aa) cannot convert the black pigment to brown. What color fur would a mouse have with the genotype aaBB

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Answer:

Black

Explanation:

In the mouse a certain colorless pigment precursor exists.

  • If the B allele is present: precursor is converted into black pigment.
  • If the genotype is bb: albino

In addition:

  • If the A allele is present: black pigment is converted to brown pigment
  • If the genotype is aa: black pigment is not converted and mouse remains black

If the mouse has a genotype aaBB, the colorless pigment is converted to black (because there is at least one B allele) but the black pigment cannot be converted into brown (because there's no A allele), so the mouse will have black fur,

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Answer:Black

Explanation:

Since the genotype is aaBB

aa- is a reccessive Allele that cannot concert black to brown hence not expressed while BB is a dominant Allele for Black fur color. BB that is dominant for black fur will be expressed in the mouse fur and it will have a black fur color

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