Against the wind a commercial airline in South America flew 630 miles in 3.5 hours. With a tailwind the return trip took 3 hours. What was the speed of the plane in still air? What was the speed of the wind?

Respuesta :

Answer:

The speed of plane is [tex]195\ mph[/tex], and speed wind is [tex]15\ mph[/tex].

Step-by-step explanation:

Given against the wind the airline flew [tex]630[/tex] miles in [tex]3.5[/tex] hours.

including the tailwind the return trip took [tex]3[/tex] hours.

Let speed of plane is [tex]x[/tex].

Also, speed of the wind is [tex]y[/tex].

Now, we will find speed on each case.

Speed against the wind is  [tex]\frac{630}{3.5}=180\ mph[/tex]

Speed with the wind is [tex]\frac{630}{3}=210\ mph[/tex]

Now, we will write the equation

[tex]x+y=210\\x-y=180[/tex]

Add these equation we get,

[tex]2x=390\\x=\frac{390}{2}\\x=195\ mph[/tex]

Now, plug this value in [tex]x+y=210[/tex] to get speed of wind

[tex]195+y=210\\y=210-195\\y=15\ mph[/tex]

So, the speed of plane in still air is [tex]195\ mph[/tex], and speed of the wind is [tex]15\ mph[/tex].

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