Answer:
The speed of plane is [tex]195\ mph[/tex], and speed wind is [tex]15\ mph[/tex].
Step-by-step explanation:
Given against the wind the airline flew [tex]630[/tex] miles in [tex]3.5[/tex] hours.
including the tailwind the return trip took [tex]3[/tex] hours.
Let speed of plane is [tex]x[/tex].
Also, speed of the wind is [tex]y[/tex].
Now, we will find speed on each case.
Speed against the wind is [tex]\frac{630}{3.5}=180\ mph[/tex]
Speed with the wind is [tex]\frac{630}{3}=210\ mph[/tex]
Now, we will write the equation
[tex]x+y=210\\x-y=180[/tex]
Add these equation we get,
[tex]2x=390\\x=\frac{390}{2}\\x=195\ mph[/tex]
Now, plug this value in [tex]x+y=210[/tex] to get speed of wind
[tex]195+y=210\\y=210-195\\y=15\ mph[/tex]
So, the speed of plane in still air is [tex]195\ mph[/tex], and speed of the wind is [tex]15\ mph[/tex].