Question

A negative charge of -0.510 μC exerts an upward 0.600-N force on an unknown charge that is located 0.300 m directly below the first charge. What are (a) the value of the unknown charge (magnitude and sign); (b) the magnitude and direction of the force that the unknown charge exerts on the −0.550μC charge?

Answer 1

(a).The value of unknown charge is $-11.76\mu C$

(b). The magnitude of force is 0.600 N and nature of force is repulsive.

(a). The Coulomb force is given as,

                  $F=k\frac{q_{1}*q_{2}}{r^{2} }$

Where $q_{1}$ and $q_{2}$ are charges and r is distance between them.

and k is constant,  $k=9*10^{9}Nm^{2}/C^{2}$

Given that, $q_{1}=-0.510\mu C=-0.510*10^{-6} C , r=0.300m,F=0.600N$

Substitute values in above equation.

                $0.600=9*10^{9} *\frac{(-0.510*10^{-6} )*q_{2}}{(0.300)^{2} }\\ \\q_{2}=-1.176*10^{-5}C=-11.76\mu C$

(b). The magnitude of force is 0.600 N and nature of force is repulsive.

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