Answer: [tex]6.241\times 10^{18}[/tex] electrons pass through a cross section of the wire each second.
Explanation:
According to mole concept:
1 mole of an atom contains [tex]6.022\times 10^{23}[/tex] number of particles.
Given : Charge on 1 electron = [tex]1.6\times 10^{-19}C[/tex]
Charge on 1 mole of electrons = [tex]1.6\times 10^{-19}\times 6.022\times 10^{23}=96500C[/tex]
To calculate the charge passed we use the equation:
[tex]I=\frac{q}{t}[/tex]
where,
I = current passed = 1 A
q = total charge = ?
t = time required = 1 sec
Putting values in above equation, we get:
[tex]1A=\frac{q}{1s}\\\\q=1A\times 1s=1C[/tex]
When 96500C of electricity is passed , the electrons passed = [tex]6.022\times 10^{23}[/tex]
1 C of electricity is passed , the electrons passed = [tex]\frac{6.022\times 10^{23}}{96500}\times 1C=6.241\times 10^{18}[/tex]
Hence, [tex]6.241\times 10^{18}[/tex] electrons pass through a cross section of the wire each second.