Respuesta :
Answer:a. Draw Punnett squares for each couple (you may need to do more than 1 square/ couple)
Baby 2 MUST belong to the Browns because Mr. Brown is the only parent with an A allele to
contribute… then the rest works out as follows:
b. To which parents does baby #1 belong? Why? Hint you may want to refer to your Punnett
squares.
Baby 1 must belong to the Smiths, because they are the only ones with the possibility of EACH
having a recessive allele to pass down to the baby, Mr. Brown has type AB blood and therefore
only has the dominant A and dominant B alleles – no recessive allele possible.
Explanation:
Baby I belongs to Mr. and Mrs. Smith.
Individuals Blood type Genotype Parents Name
Baby I O Smith Smith
Mrs. Brown B Bi
Mr. Brown AB AB
Mrs. Smith B Bi
Mr. Smith B Bi
The Punnett squares
[tex]\begin{matrix} & B & B \\ B & BB & \\ & & \end{matrix}[/tex] [tex]\begin{matrix} & B & B \\ B & BB & BB\\ i & Bi & Bi\end{matrix}[/tex]
[tex]\begin{matrix} & B & i \\ B & BB & Bi\\ i & Bi & ii\end{matrix}[/tex]
- Since, baby I have O type of blood group, so the baby should have 'i' alleles from both parents.
- This can be true only when both the parents of the baby I have 'i' allele in their genotype
Thus from the Punnett square diagram, we can say that baby I belongs to Mr. and Mrs. Smith.
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