Question

6m-2(7+3m)>5(2m-3)-m

Answer 1

Answer:

Therefore the value is

$m<\dfrac{1}{9}$

Step-by-step explanation:

Given:

$6m-2(7+3m)>5(2m-3)-m$ ....Given

Step 1. Applying Distributive Property A(B+C)=AB+AC we get

$6m-2\times7-2\times 3m>5\times 2m-5\times 3-m$

$6m-14-6m>10m-15-m\\-14>9m-15$

Step 2. Add 15 both the side

$-14+15>9m-15+15\\1>9m$

Step 3. Dividing both the side by 9

$\dfrac{1}{9}>\dfrac{9m}{9}\\\\\dfrac{1}{9}>m$

Therefore the value is

$m<\dfrac{1}{9}$